5x^2+x-(1/4)=0

Solution for 5x^2+x-(1/4)=0 equation:

5x^2+x-(1/4)=0

We add all the numbers together, and all the variables

5x^2+x-(+1/4)=0

We get rid of parentheses

5x^2+x-1/4=0

We multiply all the terms by the denominator


5x^2*4+x*4-1=0

Wy multiply elements

20x^2+4x-1=0

a = 20; b = 4; c = -1;
Δ = b2-4ac
Δ = 42-4·20·(-1)
Δ = 96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{96}=\sqrt{16*6}=\sqrt{16}*\sqrt{6}=4\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{6}}{2*20}=\frac{-4-4\sqrt{6}}{40}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{6}}{2*20}=\frac{-4+4\sqrt{6}}{40}
$